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Disaccharide

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calculate the percentage hydrolysis of NaOCN in its 0.003M aqueous solution (Ka for HOCN =3.33*10^-4M)

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Similar questions

Q. The percentage hydrolysis in

0.003 M

aqueous solution of

N a O C N

(K_{a}

H O C N

3.33 \times 10^{- 4} M)

Q. Calculate the percentage of hydrolysis in

0.003 M

aqueous solution of

N a O C N

K_{a}

H O C N = 3.33 \times 10^{- 4}

.

Q. The percentage hydrolysis in

0.003 M

aqueous solution of

N a I = O C N

(K_{a}

H O C N

3.33 \times 10^{- 4} M)

0.0 X

%. The value of X is

Q. Calculate the percentage of hydrolysis in

0.003 M

aqueous solution of

N a O C N

K_{a}

H O C N = 3.33 \times 10^{- 4}

.

The percentage of hydrolysis in $0.003 M$ aqueous solution of $N a O C N$ is:

( $K a$ for $H O C N$ = $3.33 \times 10^{- 4} M$ )

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