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Method of Substitution to Find the Solution of a Pair of Linear Equations

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Question

Calculate the percentage of available chlorine in a given sample of bleaching powder from the following data.
$3.55 g$ of bleaching powder when treated with acetic acid and excess of $K I$ liberated iodine which required $60 m L$ of $0.5 N$ sodium thiosulphate solution.

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Solution

$60 m L 0.5 N N a_{2} S_{2} O_{3} \equiv 60 m L 0.5 N I_{2}$
$\equiv 60 m L 0.5 N C l_{2}$
Amount of chlorine $= \frac{35.5 \times 0.5}{1000} \times 60 = 1.065 g$
% of available chlroine $= \frac{1.065}{3.55} \times 100 = 30.0$ .

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