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Question

Calculate the percentage of hydrolysis in 0.003 M aqueous solution of NaOCN. Ka for HOCN=3.33×104.

A
0.001
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B
0.01
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C
0.02
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D
0.1
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Solution

The correct option is B 0.01
NaOCN+H2ONaOH+HCN
HOCNH++OCN
From hydrolysis of salt, we know,
Kh=KwKa and
Degree of hydrolysis,α=(KhC)=Kw(Ka.C)
=(1014)(3.33×104×0.003)
Degree of hydrolysis=104
% of hydrolysis =104×100=102

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