Calculate the percentage of hydrolysis in 0.003M aqueous solution of NaOCN. Ka for HOCN=3.33×10−4.
A
0.001
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B
0.01
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C
0.02
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D
0.1
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Solution
The correct option is B 0.01 NaOCN+H2O⇌NaOH+HCN HOCN⇌H++OCN−
From hydrolysis of salt, we know, Kh=KwKa and Degreeofhydrolysis,α=√(KhC)=√Kw√(Ka.C) =√(10−14)√(3.33×10−4×0.003) Degreeofhydrolysis=10−4 % of hydrolysis =10−4×100=10−2