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Question

Calculate the percentage of p character of the orbitals of B atom involved in bonding with H-atom in BH3 molecule.

A
66.66%
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B
33.33%
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C
50%
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D
75%
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Solution

The correct option is A 66.66%
The ground state electronic configuration of B atom is: 1s22s22p1

The excited state electronic configuration of B atom is: 1s22s12p2

Thus, here 2s orbital and two 2p orbitals undergoes hybridisation to give three sp2 hybridised orbitals. Hence, boron in BH3 is sp2 hybridised.

Thus, the percentage of p character of the hybridised orbital of B in BH3 molecule is 23×100=66.66 %

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