Calculate the percentage of phosphorus in the fertilizer, superphosphate Ca(H2PO4)2.(Correct to 1 decimal point). [H = 1, O = 16, P = 31, C = 40]
26.5 %
Molecular weight of Ca(H2PO4)2
= 40+2(2×1+31+4×16)
= 40+2×97
=40+194
=234 g.
Amount of phosphorous in Ca(H2PO4)2
= 2 × 31 = 62 g.
Percentage of phosphorous = 62×100234 = 26.5%