Question

Calculate the percentage of water in ferrous sulphate crystal.[Fe: 56, S:32, O:16, H:1]

Answer 1

The formula of ferrous sulphate is FeSO₄.7H₂O .
Molar mass of ferrous sulphate crystal = 278 g /mol
Mass of water in salt is : $7\times 18=126g$
$Thepercentageofwaterinsalt=\frac{126}{278}\times 100=45.32\%$