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Characteristics of Equilibrium Constant

Calculate the...

Question

Calculate the $p H$ at $25^{\circ}$ of a solution that is 0.10 M in $F e (N O_{3})_{3}$ . The acid dissociation constant for the reaction given below is $1.0 \times 10^{- 3}$ .
$[F e (H_{2} O)_{6}]^{3 +} + H_{2} O (l) ⇌ H_{3} O^{+} (a q .) + [F e (H_{2} O)_{5} (O H)]^{2 +}$

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2.02

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2.3

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2.5

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Solution

The correct option is B 2.02
α

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Similar questions

H_{2} C_{2} O_{4} (a q) + H_{2} O (l) ⇌ H_{3} O + (a q) + H C_{2} O_{4} - (a q)

H C_{2} O_{5} - (a q) + H_{2} O (l) ⇌ H_{3} O + (a q) + C_{3} O_{4}^{2} - (a q)

K_{c l} = 5.9 \times 10^{- 2}

K_{c 2} = 6.4 \times 10^{- 5}

25^{\circ} C

K_{c}

(3)

H_{2} C_{2} O_{4} (a q) + 2 H_{2} O (l) ⇌ 2 H_{3} O + (a q) + C_{2} O_{4}^{2} - (a q)

p H

0.10 M

N a C N (a q), K_{a}

H C N

4.9 \times 10^{- 10}

25^{o} C

K_{a}

F e^{3 +} (a q .) + H_{2} O (l) ⇌ F e (O H)^{2 +} (a q .) + H_{3} O^{+} (a q .)

6.5 \times 10^{- 3}

p H

80 %

(I I I)

F e^{3 +}

H_{2} O_{(l)} + H_{2} O_{(l)} ⇌ H_{3} O_{(a q)}^{+} + O H_{(a q)}^{-}

25^{\circ} C

1.0 \times 10^{- 4}

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