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Question

Calculate the pH at which an acid indicator HIn with concentration 0.1 M changes its colour.
(Ka for HIn=1×105)

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Solution

This indicator (HIn) is a weak acid.
HIn+H2OH3O++In
Ks=[H3O+][In][HIn]
=[H3O+] [Since at equivalence point the concentration of indicator and it's conjugate base are equal.]
pKs=pH
pH=pKIn=5

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