Calculate the pH for 5 - 10-5 M Ca OH 2A- 4B- 5C- 9D- 10

Ca(OH)_2(aq) → nbsp;Ca^2+(aq)+2OH^ (aq) 1 Ca(OH)_2 nbsp; gives 2 OH^ ions ∴ OH^ ions concentration=2×(5× 10^ 5M) [OH^ ]=10×10^ 5 M pOH= log_10[OH^ ] ...

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Standard X

Chemistry

Calculate the...

Question

Calculate the pH for $5 \times 10^{- 5} M C a (O H)_{2}$

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Solution

The correct option is B 10
$C a (O H)_{2} ⇌ C a^{2 +} + 2 O H^{-} 1 C a (O H)_{2} i o n g i v e s 2 O H^{-} i o n s ∴ O H^{-} i o n s c o n c e n t r a t i o n = 2 \times (5 \times 10^{- 5}) [O H^{-}] = 10 \times 10^{- 5} p O H = - l o g_{10} (10 \times 10^{- 5}) p O H = - (1 - 5) = 4 p H = 14 - 4 = 10$
hence, the pH for $5 \times 10^{- 5} M C a (O H)_{2}$ is 10.

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Standard X Chemistry

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Calculate the pH for 5×10−5 M Ca(OH)2

The correct option is B 10Ca(OH)2⇌Ca2++2OH−1 Ca(OH)2 ion gives 2 OH− ions∴ OH− ions concentration=2×(5×10−5)[OH−]=10×10−5pOH=−log10(10×10−5)pOH=−(1−5)=4pH=14−4=10 hence, the pH for 5×10−5 M Ca(OH)2 is 10.

Calculate the pH for $5 \times 10^{- 5} M C a (O H)_{2}$