Calculate the pH of 0-1M CH3COOHKa-1-8-10-5-

[H^+]=√(KaC)=√(1.8×10^ 6) =1.34×10^ 3 pH= log[H^+] #160; #160; #160; = 2.88 ...

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pH of a Solution

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Question

Calculate the pH of $0.1 M$ ${C H}_{3} C O O H (K_{a} = 1.8 \times 10^{- 5})$ :

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Solution

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0.1

H C l

0.1 M

0.1 M

{N H}_{4} C l

O H = 1.8 \times 10^{- 5}, K_{b} ({N H}_{3}) = 1.8 \times 10^{- 5}

K_{a} = 1.8 \times 10^{- 5}

K_{b} = 1.8 \times 10^{- 5} (p K_{a} = p K_{a} = 4.7447)

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{C H}_{3} C O O H

5.0 m L

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p H

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{C H}_{3} C O O H

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K_{a} = 1.8 \times 10^{- 5}

K_{b} = 1.8 \times 10^{- 5}

N H_{4} O H

1.344 %

K_{b}

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