wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Calculate the pH of 106M CH3COOH
Take Ka=2×105

Open in App
Solution

We have,
The concentration of CH3COOH is 106M
and Ka=2×105
Now we have,
Ka=[H+][CH3COO][CH3COOH]
let the equilibrium concentration of [H+] and [CH3COOH] be x.
2×105=x2106
x2=2×1011
x=4.47×1012
Now pH=log10[H+]
pH=log(4.47×1011)
pH=11.35

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
pH of a Solution
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon