Question

Calculate the $pH$ of a solution made by mixing $50mL$ of $0.01M$ $Ba{\left(OH\right)}_2$ with $50mL$ of water.

Answer 1

First calculate the hydroxide ion concentration.
$\left[O{H}^{-}\right]=\frac{2\times 50mL\times \frac{0.01mol}{1L}}{50mL+50mL}=0.01M$
Now calculate the pOH of solution.
$pOH=-log\left[O{H}^{-}\right]=-log0.01=2$
Now calculate the pH of solution.
$pH=14-pOH=14-2=12$.
Hence, the pH of solution is 12.