Question

Calculate the $pH$ of a solution obtained by diluting $25$ ml of decinormal $HCl$ to $500$ ml assuming complete ionisation of $HCl$.

Answer 1

Concentration of dilutted Hcl solution

will be :-

$25x0.1/500=0.005N$

$\therefore PH$ of solution = log (0.005)

= 2.3010 (ans)