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Question

Calculate the pH of a solution prepared by mixing 2.0 ml of a strong acid (HCl) solution of pH 3.0 and 2.0 ml of a strong base (NaOH) of pH 11.0

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Solution

Number of milliequivalents of HCl
=2×103
We know that pH + pOH = 14.
11+pOH=14
pOH=3
[OH]=103M
2 ml of 103 M NaOH=2×103
Number of milliequivalents of NaOH = 2×103
The resulting solution is neutral since the number of meq of acid and base are the same.
The pH would be 7.

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