Calculate the pH of following solutions: $Pt, H_{2} | H C l, E = 0.25 V$

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Solution

$\frac{1}{2} H_{2} \to H^{+} + e^{-}$
E = $E^{0} - \frac{0.0591}{n} l o g H^{+}$
0.25 = 0 + $\frac{0.0591}{1} p H$
pH = 4.230

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