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Byju's Answer
Standard XII
Chemistry
Basic Buffer Action
Calculate the...
Question
Calculate the pH of the buffer solution containing
0.15
m
o
l
e
of
N
H
4
O
H
and
0.25
m
o
l
e
of
N
H
4
C
l
.
K
b
for
N
H
4
O
H
is
1.8
×
10
−
5
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Solution
Applying the equation
p
O
H
=
log
[
S
a
l
t
]
[
B
a
s
e
]
−
log
K
b
=
log
0.25
0.15
−
log
1.8
×
10
−
5
=
4.966
p
H
=
(
14
−
4.966
)
=
9.034
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Similar questions
Q.
Concentration of
N
H
4
C
l
and
N
H
4
O
H
in a buffer solution are in the ratio of 1:10, Kb for
N
H
4
O
H
is
10
−
10
. The pH of the buffer is:
(BHU, 1994)
Q.
Calculate the pH of that buffer soln which is obtained by dissolving 0.2 moles of
N
H
4
O
H
& 0.25 mole of
N
H
4
C
l
in water.
K
b
=
1.8
×
10
–
5
Q.
Calculate the mass of
N
H
4
C
l
dissolved in
500
m
l
to have
p
H
=
4.5
. (
K
b
of
N
H
4
O
H
=
1.8
×
10
−
5
)
Q.
Calculate the
p
H
of
0.1
M
N
H
4
C
l
solution in water :
K
b
(
N
H
4
O
H
)
=
1.8
×
10
−
5
,
l
o
g
1.8
=
0.25
Q.
In a basic buffer,
0.0025
mole of
N
H
4
C
l
and
0.15
m
o
l
e
of
N
H
4
O
H
are present. The
p
H
of the solution will be:
(
p
K
a
)
=
4.74
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