Question

Calculate the pH of the resultant mixtures:

a) 10 mL of 0.2M Ca(OH)₂ + 25 mL of 0.1M HCl

b) 10 mL of 0.01M H₂SO₄ + 10 mL of 0.01M Ca(OH)₂

c) 10 mL of 0.1M H₂SO₄ + 10 mL of 0.1M KOH

Answer 1

(a)

Thus, excess of = .0015 mol

(b)

Since there is neither an excess of or, the solution is neutral. Hence, pH = 7.

(c)

Excess of = .001 mol

= 1.30