Calculate the pH value in $10^{- 8} M$ NaOH:

7.04

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6.96

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Solution

The correct option is B 6.96
The hydroxide ion concentration in neutral water is $10^{- 7}$ .
The hydroxide ion concentration in $10^{- 8}$ M NaOH solution will be $10^{- 7} + 10^{- 8} = 10^{- 7} \times 1.1$
$p O H = - l o g [H^{+}] = - l o g 10^{- 7} \times 1.1 = 7 - l o g 1.1 = 6.96$ .

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