Question

Calculate the $pH$ value of $0.03NHCl$ solution.

Answer 1

$pH=-log\left[H^{+}\right]$

$0.03NHCl\to \left[H^{+}\right]=3\times {10}^{2-}$

$pH=-log[3\times {10}^{2-}]$

$=2log3$

$=1.52$