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Ostwald Dilution Law

Calculate the...

Question

Calculate the $p H$ value of $H {N O}_{3}$ solution containing $0.315 g$ acid in $200 m l$ of solution.
( $log 2.5 = 0.3979$ )

1.6021

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0.3979

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Solution

The correct option is B $1.6021$
Moles of $H N O_{3} = \frac{w e i g h t}{M o l e c u l a r w e i g h t} = \frac{0.315}{63} = 0.005 m o l e$

Concentration of $H^{+}$ ions = $\frac{0.005}{0.2} = 0.025 M$

$p H = - l o g [0.025] = 1.602$

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