Calculate the pOH of a solution at 25- C that contains 1 - 10-10 M of hydronium ions- i-e- H 3 O -A- 7-000B- 4-000C- 9-000D- 1-000

The correct option is B 4.000 We know that [H^+] × [OH^ ] = 10^ 14 [OH^ ] = 10^ 4 mol By definition, pOH = log [OH^ ] = 4 ...

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Standard XII

Chemistry

Factors Affecting Alpha

Calculate the...

Question

Calculate the $p O H$ of a solution at $25^{\circ} C$ that contains $1 \times 10^{- 10} M$ of hydronium ions, i.e., $H_{3} O^{+};$

1.000

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7.000

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4.000

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9.000

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Solution

The correct option is C
4.000

We know that $[H^{+}] \times [O H^{-}] = 10^{- 14}$

$⟹ [O H^{-}] = 10^{- 4} m o l$

By definition, $p O H = - l o g [O H^{-}] = 4$

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Calculate the pOH of a solution at 25∘C that contains 1×10−10M of hydronium ions, i.e., H3O+;

The correct option is C 4.000 We know that [H+]×[OH−]=10−14 ⟹[OH−]=10−4mol By definition, pOH=−log[OH−]=4

Calculate the $p O H$ of a solution at $25^{\circ} C$ that contains $1 \times 10^{- 10} M$ of hydronium ions, i.e., $H_{3} O^{+};$

The correct option is C
4.000

We know that $[H^{+}] \times [O H^{-}] = 10^{- 14}$

$⟹ [O H^{-}] = 10^{- 4} m o l$

By definition, $p O H = - l o g [O H^{-}] = 4$