Question

Calculate the potential at a point due to a charge of $3\times {10}^{-9}C$ located $9\times {10}^{-2}m$ away from it.

Answer 1

The electric potential at a distance $r$ from charge $q$ is given as

$\frac{1}{4\pi {ϵ}_0}\frac{q}{r}$

$=9\times {10}^9\times \frac{3\times {10}^{-9}}{9\times {10}^{-2}}V$

$=300V$