Question

Calculate the potential at a point due to a charge of $4\times {10}^{-7}C$ located at $0.09m$ away.

Answer 1

Given data:
$q_1=4\times {10}^{-7}C,r=0.09m$
The potential due to the charge $q_1$ at a point is
$V=\frac{1}{4\pi {ϵ}_0}\frac{q_1}{r}$
$=\frac{9\times {10}^9\times 4\times {10}^{-7}}{0.09}=4\times {10}^{4}V$