Question

Calculate the power developed by an amplitude modulated wave in a load resistance of $100\Omega$, if the peak voltage of carrier wave is $100V$ and modulation index is $0.4$.

• A. $50watt$
• B. $54watt$
• C. $104watt$
• D. $4watt$

Answer 1

Answer: (B)

$54watt$

$E_c=100V$, $m_a=0.4$, $R=100\Omega$,
$P_c=\frac{{E_c}^2}{2R}=\frac{{\left(100\right)}^2}{2\times 100}=50watt$
$P=(1+\frac{{m_a}^2}{2})P_c=(1+\frac{{\left(0.4\right)}^2}{2})\times 50=54watt$