Calculate the power of a pump which can lift 100 kg of water to store it in a water tank at a height of 19 m in 25 s. (Take the value of g = 10 $\frac{m}{s^{2}}$ )

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Solution

Given:
Mass(m) = 100 kg
Height (h) =19 m
Time(t) = 25 s
Calculation:
$P o w e r (P) = \frac{E n e r g y (E)}{T i m e (t)} P o w e r (P) = \frac{100 k g \times 10 \frac{m}{s^{2} \times 19 m}}{25 s} P o w e r (P) = 760 W$
Hence, the power of a pump is 760 W.

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Calculate the power of a pump which can lift 100 kg of water to store it in a water tank at a height of 19 m in 25 s. (Take the value of g = 10 ms2)

Given:Mass(m) = 100 kgHeight (h) =19 mTime(t) = 25 sCalculation:Power(P)=Energy(E)Time(t)Power(P)=100kg×10ms2×19m25sPower(P)=760WHence, the power of a pump is 760 W.

Calculate the power of a pump which can lift 100 kg of water to store it in a water tank at a height of 19 m in 25 s. (Take the value of g = 10 $\frac{m}{s^{2}}$ )

Given:
Mass(m) = 100 kg
Height (h) =19 m
Time(t) = 25 s
Calculation:
$P o w e r (P) = \frac{E n e r g y (E)}{T i m e (t)} P o w e r (P) = \frac{100 k g \times 10 \frac{m}{s^{2} \times 19 m}}{25 s} P o w e r (P) = 760 W$
Hence, the power of a pump is 760 W.