Calculate the power of soldering iron with a hot resistance 4 K- and operating voltage of 200 V-

Given: R=4 KΩ V=200 V Power=V^2R=(200)^2(4× 10^3) , P =4× 10^44× 10^3 #160; P =10 W ...

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Question

Calculate the power of soldering iron with a hot resistance $4$ $K Ω$ and operating voltage of $200$ $V$ .

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Solution

Given:
$R = 4$ $K Ω$
$V = 200$ $V$
$P o w e r = \frac{V^{2}}{R} = \frac{(200)^{2}}{(4 \times 10^{3})}$ , $P$ $= \frac{4 \times 10^{4}}{4 \times 10^{3}}$
$P$ $= 10$ $W$

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Calculate the power of soldering iron with a hot resistance 4 KΩ and operating voltage of 200 V.

Given:R=4 KΩV=200 VPower=V2R=(200)2(4×103) , P =4×1044×103 P =10 W

Calculate the power of soldering iron with a hot resistance $4$ $K Ω$ and operating voltage of $200$ $V$ .

Given:
$R = 4$ $K Ω$
$V = 200$ $V$
$P o w e r = \frac{V^{2}}{R} = \frac{(200)^{2}}{(4 \times 10^{3})}$ , $P$ $= \frac{4 \times 10^{4}}{4 \times 10^{3}}$
$P$ $= 10$ $W$