Calculate the pressure at a depth of $50 m$ below the surface of the sea. The density of sea water is $1024 k g / m^{3}$ .

( Accelaration due to gravity = $10 m / s^{2}$ )

512000 Pa

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51200 Pa

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5120 Pa

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None of these

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Solution

The correct option is A
512000 Pa

The expression of pressure at the bottom of a liquid of height ‘h’ and density ‘d’ is given by $d g h$ .
The given values are:
$d = 1024 k g / m^{3}$ , $h = 50 m$ and $g = 10 m / s^{2}$
Thus, $p r e s s u r e = d g h = 1024$ $\times$ 50 $\times 10 = 512000 P a$ .

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Calculate the pressure at a depth of 50m below the surface of the sea. The density of sea water is 1024 kg/m3. ( Accelaration due to gravity = 10m/s2)

The correct option is A 512000 Pa The expression of pressure at the bottom of a liquid of height ‘h’ and density ‘d’ is given by dgh. The given values are: d=1024kg/m3, h=50m and g=10m/s2 Thus, pressure=dgh=1024 × 50 ×10=512000Pa.

Calculate the pressure at a depth of $50 m$ below the surface of the sea. The density of sea water is $1024 k g / m^{3}$ .

( Accelaration due to gravity = $10 m / s^{2}$ )