Calculate the pressure exerted by 0.8 m vertical length of alcohol of density 0.80 g cm^-3 in SI units. (Take g=10 m/s)

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Solution

Step 1. Given data
Height of alcohol column, $h = 0.8 m$ ,
Density of alcohol, $ρ = 0.80 g / c m^{3} = 800 k g / m^{3}$ ,
Acceleration due to gravity, $g = 10 m / s^{2}$ , and
To find, Pressure exerted by alcohol, $P$
Step 2. Formula used
$P = h \times ρ \times g$
Step 3. Calculation of the pressure exerted by the alcohol
$P = 0.8 m \times 800 k g / m^{3} \times 10 m / s^{2} P = 6400 N / m^{2} P = 6400 P a$
Hence, the pressure exerted by 0.8 m alcohol height is 6400 Pa.

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Calculate the pressure exerted by 0.8 m vertical length of alcohol of density 0.80 g cm-3 in SI units. (Take g=10 m/s)

Calculate the pressure exerted by 0.8 m vertical length of alcohol of density 0.80 g cm^-3 in SI units. (Take g=10 m/s)