calculate the pressure exerted by 0.8 vertical length of alcohol of density 0.80 gram centimetre cube in SI units

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Solution

Dear student,
$V e r t i c a l l e n g t h o f a l c o h o l c o l u m n = h = 0.8 m D e n s i t y o f a l c o h o l = ρ = 0.80 g c m^{- 3} ρ = \frac{0.80 \times 10^{6}}{10^{3}} k g m^{- 3} ρ = 0.80 \times 1000 k g m^{- 3} . ρ = 800 k g m^{- 3} P r e s s u r e = h p g P = 0.8 \times 800 \times 10 = 6400 P a$

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calculate the pressure exerted by 0.8 vertical length of alcohol of density 0.80 gram centimetre cube in SI units

Dear student, Vertical length of alcohol column = h = 0.8 m Density of alcohol = ρ = 0.80 g cm-3 ρ=0.80×106103kgm-3 ρ = 0.80 × 1000 kgm-3 . ρ = 800 kgm-3 Pressure = hpg P = 0.8 × 800 × 10 = 6400 Pa Regards