Question

Calculate the pressure exerted by 76 cm column of mercury.

Answer 1

We know:
P = h$\mathrm{\rho }$g

Density of mercury, $\mathrm{\rho }$ =$13.6\times {10}^3{\mathrm{kg}}^{-3}\mathrm{m}$
Height of the column of mercury, h = 76 cm = 0.76 m

P = h$\mathrm{\rho }$g

$$\begin{gathered} \mathrm{P}=0.76\times (13.6\times {10}^3)\times 9.8 \\ \mathrm{P}=1.013\times {10}^5{\mathrm{Nm}}^{-2}\mathrm{or}\mathrm{Pa} \end{gathered}$$