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Question

Calculate the pressure exerted by one mole of CO2 gas at 273K, if the van der Waals constant a=3.592 dm6 atm mol2. Assume that the volume occupied by CO2 molecules is negligible.

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Solution

According to van der Waals equation of state for 1 mole of as gas,
( P +aV2 ) (V-b) =0
Since, the volume occupied by CO2 molecules is negligible, b =0
So,
( P +aV2 ) V = RT
or,
P = RTV2 - aV2

= 0.082×27322.4 - 3.592(22.4)2
= 0.999375 - 0.0071588
= 0.9922 atm

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