Question

Calculate the pressure exerted by water at the bottom of a lake of depth 6 m. (Density of water $=1000kg{m}^{-3},g=10m{s}^{-2})$.

• A. $2\times {10}^{4}Pa$
• B. $4\times {10}^{4}Pa$
• C. $6\times {10}^{4}Pa$
• D. $8\times {10}^{4}Pa$

Answer 1

Answer: (C)

$6\times {10}^{4}Pa$

Height $\left(h\right)=6m$,

$density=1000kg{m}^{-3}$,

$g=10m{s}^{-2},Pressure=?$

$P=hdg$

$=6\times 1000\times 10Pa$

$=60000Pa$

$=6\times {10}^{4}Pa.$