Question

Calculate the pressure in pascal exerted by a force of 300 N acting normally on an area of $30c{m}^2$.

Answer 1

F = 300 N

A = 300 $c{m}^2$ = $\frac{30}{100\times 100}$ = 30 $\times$ ${10}^{-4}$ $m^2$

P = $\frac{F}{A}$

P = $\frac{300}{30\times {10}^{-4}}$

= 100000

= ${10}^5$