Calculate the pressure inside a small air bubble of radius r situated at a depth h below the free surface of liquids of densities -1 and -2 and surface tension T1 and T2- The thickness of the first and second liquids are h1 and h2- respectively- Take atmosphere pressure -P0-

The correct option is B P _ 0 +ρ_ 1 gh _ 1 +ρ_ 2 g( h h _ 1 ) + 2 T _ 2 r P_c=P_B+2Tr P_B=P_A+ρ_1gh_1+ρ_2g(h h_1) where P_A=P_0 P_c ...

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Standard XII

Physics

Pascal's Law

Calculate the...

Question

Calculate the pressure inside a small air bubble of radius $r$ situated at a depth $h$ below the free surface of liquids of densities $ρ_{1}$ and $ρ_{2}$ and surface tension $T_{1}$ and $T_{2}$ . The thickness of the first and second liquids are $h_{1}$ and $h_{2}$ , respectively. Take atmosphere pressure $= P_{0}$ .

P_{0} + ρ_{1} {g h}_{1} + ρ_{2} g (h - h_{1}) - \frac{2 T_{2}}{r}

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P_{0} + ρ_{1} {g h}_{1} + ρ_{2} g (h - h_{1}) + \frac{2 T_{2}}{r}

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P_{0} - ρ_{1} {g h}_{1} + ρ_{2} g (h - h_{1}) + \frac{2 T_{2}}{r}

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Solution

The correct option is B $P_{0} + ρ_{1} {g h}_{1} + ρ_{2} g (h - h_{1}) + \frac{2 T_{2}}{r}$
$P_{c} = P_{B} + \frac{2 T}{r}$

$P_{B} = P_{A} + ρ_{1} g h_{1} + ρ_{2} g (h - h_{1})$

where $P_{A} = P_{0}$

$P_{c} = P_{0} + ρ_{1} g h_{1} + ρ_{2} g (h - h_{1}) + \frac{2 T_{2}}{r}$

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Calculate the pressure inside a small air bubble of radius r situated at a depth h below the free surface of liquids of densities ρ1 and ρ2 and surface tension T1 and T2. The thickness of the first and second liquids are h1 and h2, respectively. Take atmosphere pressure =P0.

The correct option is B P0+ρ1gh1+ρ2g(h−h1)+2T2rPc=PB+2TrPB=PA+ρ1gh1+ρ2g(h−h1)where PA=P0Pc=P0+ρ1gh1+ρ2g(h−h1)+2T2r

The correct option is B $P_{0} + ρ_{1} {g h}_{1} + ρ_{2} g (h - h_{1}) + \frac{2 T_{2}}{r}$
$P_{c} = P_{B} + \frac{2 T}{r}$

$P_{B} = P_{A} + ρ_{1} g h_{1} + ρ_{2} g (h - h_{1})$

where $P_{A} = P_{0}$

$P_{c} = P_{0} + ρ_{1} g h_{1} + ρ_{2} g (h - h_{1}) + \frac{2 T_{2}}{r}$