Calculate the probability of scoring a total of 7 at least once in two tosses of a pair of fair dice.
A
518
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B
13
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C
1136
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D
136
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Solution
The correct option is C1136 P(rolling a seven) =P(A)=636=16 P( not rolling a seven) =P(B)=1−P(A)=1−16=56 Here, we may observe that it is certain we will either roll a 7 at least once or not roll a seven P(C)+P(B).P(B)=1P(C)=1−(P(B))2 P(C)=1−(56)2=1−2536=1136