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Units and Dimensions

Calculate the...

Question

Calculate the product of boiling point of water and melting point of water in Celsius scale.

A

0^{o} C

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B

273^{o} C

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C

100^{o} C

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D

373^{o} C

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Solution

The correct option is A $0^{o} C$
The boiling point of water $= 100^{o} C = 373 K$

The melting point of water $= 0^{o} C = 273 K$

Product $= 0 \times 100 = 0$

So, the correct option is $A$

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Similar questions

Q. Find the ratio of boiling point of water and melting point of water in Celsius scale.

Q. Why is it wrong in taking the melting point of ice and the boiling point of water as standard fixed points (as was originally done in the celsius scale)?

Q. On Reaumer scale of temperature the melting point of ice and the boiling point of water are taken as 0R and 80R respectivel. The freezing point and boiling point of mercury on Celsius scale are 39C and 367C respectively. Express these temperature on Reaumer scale.

Q. Answer the following:

(a) The triple-point of water is a standard fixed point in modern thermometry. Why? What is wrong in taking the melting point of ice and the boiling point of water as standard fixed points (as was originally done in the Celsius scale )?

(b) There were two fixed points in the original Celsius scale as mentioned above which were assigned the number

0^{o} C

100^{o} C

respectively. On the absolute scale one of the fixed points is the triple-point of water, which on the kelvin absolute scale is assigned the number 273.16 K. What is the other fixed point on this (kelvin) scale?

(c) The absolute temperature (Kelvin scale ) T is relate to the temperature

t_{c}

on the Celsius scale by

t_{c} = T - 273.15

. Why do we have 273.15 in this relation and not 273.16?

(d) What is the temperature of the triple-point of water on an absolute scale whose unit interval size is equal to that of the Fahrenheit scale ?

Q. In Celsius scale zero degree

(0^{o} C)

is defined as the ice point, the temperature of mixture of ice and water in equilibrium at 1 atmosphere.

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