Question

Calculate the Q-value of the fusion reaction

${}^{4}He{+}^{4}He{=}^{8}Be$.

Is such a fusion energetically favourable? Atomic mass of of ${}^{8}Be$ is 8.0053 u and that of ${}^{4}He$ is 4.0026 u.

Answer 1

Required value

= $(2\times 4.0026-8.0053)u{C}^2$

= $0.0001\times 931\frac{MeV}{C^2}\times C^2$

= $0.0001\times 931\times {10}^{6}eV$

= 93.1 KeV