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Question

Calculate the Q-values of the following fusion reactions:

(a) 21H+21H31H+11H

(b) 21H+21H23He+n

(c) 21H+31H24He+n

Atomic masses are m(21He)=2.014102 u,m(31He)=3.016049 u,m(32He)=3.016029 u,m(42He)=4.002603 u.

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Solution

(a) Q = [2×m21Hm31H+m11H]C2

= (4.028204-4.023874) 931 MeV

= 4.03 MeV

(b) Q = [2×m21 H(m32 H+n)]C2

= [4.028204 - 4.024694) ×231

= 0.0351×931

= 3.26 MeV

(c) Q = [m21 H+m31 Hm41 Hemn] 931

= (2.014102 + 3.016049- 4.002603-1.008665) 931

= 17.58 Mev


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