Question

Calculate the quantity of heat produced in a $20$ resistor carrying $2.5\mathrm{A}$ current in$5$ minutes.

Answer 1

Step 1: Given data

Resistance of resistor, $\mathrm{R}=20\mathrm{\Omega }$

Current, $\mathrm{I}=2.5\mathrm{A}$

Time, $\mathrm{t}=5\mathrm{minutes}$

Step 2: Finding heat produced in a resistor

We know that heat produced in a resistor is

$$\begin{gathered} \mathrm{H}={\mathrm{I}}^2\mathrm{Rt} \\ \mathrm{H}={\left(2.5\right)}^2\times 20\times 5\times 60 \\ \mathrm{H}=37500\mathrm{J} \end{gathered}$$ (Where H is the heat produced, I is current, R is the resistance and T is the time)

Hence, the quantity of heat produced is $37500\mathrm{Joule}$.