Calculate the quantity of heat required to rise the temperature of 5k of iron from 303k to 343 k ( specific heat capacity of iron is 460 j/kg k)

Open in App

Solution

First you need the below equation Q=m×c×ΔT
.
Where, m=5 of ΔT= The temperature change that occurs
that is - 40°

c - 460

So ,
Q = 546040
= 92000kj

Suggest Corrections

Similar questions

Q. Calculate the quantity of heat required to raise the temperature of

5 k g

iron from

303 K

343 K

. (Specific heat capacity of iron is

460 J k g^{- 1} K^{- 1}

)

Q. Calculate the heat needed to raise the temperature of

20 g

iron from

25^{o} C

500^{o} C

, if specific heat capacity of iron is

0.45 J K^{- 1}

g^{- 1}

42000 J

of heat energy is supplied to

175 g

of iron at

30^{o} C

, when the final temperature recorded is

430^{o}

. Calculate specific heat capacity of iron

$400 g$ of iron is heated to increase its temperature by $10^{\circ} C$ . If the same quantity of heat is given to $200 g$ of water, the rise in its temperature is ___ $^{\circ} C$ (specific heat of iron = $420 J / k g /^{\circ} C$ , specific heat of water = $4200 J / k g /^{\circ} C$ )

Q. If the specific heat capacity of iron is 0.108 cal/g'C. Then how much heat is sufficient to raise the temperature of 1 g of iron through 1'C?

Join BYJU'S Learning Program

Calculate the quantity of heat required to rise the temperature of 5k of iron from 303k to 343 k ( specific heat capacity of iron is 460 j/kg k)

First you need the below equation Q=m×c×ΔT . Where, m=5 of ΔT= The temperature change that occurs that is - 40° c - 460 So , Q = 5*460*40 = 92000kj

First you need the below equation Q=m×c×ΔT
.
Where, m=5 of ΔT= The temperature change that occurs
that is - 40°

c - 460

So ,
Q = 546040
= 92000kj