Question

Calculate the ratio of current flowing through the battery at t = 0 and t=$\infty$. (t=0 is the tine of closing of switch)-

• A. 1
• B. 2
• C. $\frac{1}{2}$
• D. $0$

Answer 1

The correct option is A 1

At $t=0$

capacitor acts as short circuit and inductor acts as open circuit

At $t=0$ circuit is equivalent

$I_1=\frac{20}{10}=2A$

At $t=\infty$ capacitor acts as open circuit and inductor as short cicuit diagram will be$:$

$I_2=\frac{20}{10}2A$

$Ratio=\frac{I_1}{I_2}=\frac{2A}{2A}=1$

Hence,

option $\left(A\right)$ is correct answer.