Calculate the ratio of pH of a solution containing 1 mol of CH3COONa + 1 mol of HCl per litre to another solution containing 1 mol of CH3COONa + 1 mol of acetic acid per litre.
The correct option is C 1:2
1 1 0 0
So, [H+]=√Ka.c =√Ka (Since c = 1)
= pH1=−12logKa = 12pKa
For IInd solution, its a mixture of acetic acid and its salt
Concentration of the acid and the salt are given, using that we get pH2=pKa
On calculating their ratio we get,