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Question

Calculate the ratio of pH of a solution containing 1 mol of CH3COONa + 1 mol of HCl per litre to another solution containing 1 mol of  CH3COONa + 1 mol of acetic acid per litre.


A
1:1
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B
2:1
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C
1:2
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D
2:3
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Solution

The correct option is C 1:2
CH3COONa+HClCH3COOH+NaCl
     1                         1                   0         0
CH3COOHCH3COO+H+
So, [H+]=Ka.c =Ka (Since c = 1)
= pH1=12logKa = 12pKa
For IInd solution, its a mixture of acetic acid and its salt
using formula
pH2=pKa+log[salt][acid]
Concentration of the acid and the salt are given, using that we get pH2=pKa
On calculating their ratio we get,
pH1pH2=12

 

Chemistry

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