Question

Calculate the ratio of rate of effusion of $O_2$ and $H_2$ from a container containing 16 $g$ $O_2$ and 2 $g$ $H_2$:

• A. 1 : 8
• B. 8 : 1
• C. 1 : 4
• D. 4 : 1

Answer 1

The correct option is A 1 : 8

Rate of effusion:

$\frac{r_{O_2}}{r_{H_2}}=\frac{n_{O_2}}{n_{H_2}}\sqrt{\frac{M_{H_2}}{M_{O_2}}}$

16g of $O_2$ = 0.5 mole and 2g of $H_2$ =1 mole.

$\frac{r_{O_2}}{r_{H_2}}=\frac{0.5}{1}\sqrt{\frac{2}{32}}=1/8$

Hence, the correct option is A.