Question

Calculate the ratio of the catalysed and uncatalysed rate constant at ${20}^{o}C$ if the energy of activation of a catalysed reaction is $20$ $kJ$ ${mol}^{-1}$ and for the uncatalysed reaction is $75$ $kJ$ ${mol}^{-1}$.

Answer 1

$\frac{K_2}{K_1}=\frac{{\epsilon a}_1}{{\epsilon a}_2}$

$K_2\to$ catalysed rate const.

$K_1\to$ uncatalysed rate const.

$\frac{K_2}{K_1}=\frac{75}{20}=3.75$