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Standard XII

Physics

Ampere's Circuital Law

Calculate the...

Question

Calculate the reading of voltmeter between X and Y then ( $V_{X} - V_{Y}$ ) is equal to

10 V

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13.33 V

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23.33 V

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10.33 V

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Solution

The correct option is C 23.33 V
$\begin{matrix} V_{x} = \frac{θ_{1}}{2 F} = \frac{θ_{2}}{3 F} = V_{y} V_{x} - V_{y} = 10 + \frac{40}{3} = \frac{70}{3} C_{e q} = 3 F θ = 60 θ_{1} = \frac{1}{3} \times 60 = 20 θ_{2} = \frac{2}{3} \times 60 = 40 \end{matrix}$

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Calculate the reading of voltmeter between X and Y then (VX−VY) is equal to

The correct option is C 23.33 VVx=θ12F=θ23F=VyVx−Vy=10+403=703Ceq=3Fθ=60θ1=13×60=20θ2=23×60=40

Calculate the reading of voltmeter between X and Y then ( $V_{X} - V_{Y}$ ) is equal to

The correct option is C 23.33 V
$\begin{matrix} V_{x} = \frac{θ_{1}}{2 F} = \frac{θ_{2}}{3 F} = V_{y} V_{x} - V_{y} = 10 + \frac{40}{3} = \frac{70}{3} C_{e q} = 3 F θ = 60 θ_{1} = \frac{1}{3} \times 60 = 20 θ_{2} = \frac{2}{3} \times 60 = 40 \end{matrix}$