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Electrochemical Series

Calculate the...

Question

Calculate the redox potential of $F e^{3 +} | F e^{2 +}$ electrode at pH = 2.

0.8 V

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0.5 V

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0.2 V

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0.1 V

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Solution

The correct option is D $0.8 V$
$F e^{3 +} + e^{-} \to F e^{2 +}$
When $F e (O H)_{3}$ precipitates, $K_{s p} = [F e^{3 +}] [⊖ O H]^{3}$
$∴ [F e^{3 +}] = \frac{K_{s p}}{[⊖ O H]^{3}} = \frac{10^{- 37}}{[⊖ O H]^{3}}$
AtpH = 4,
$E_{c e l l} = E_{c e l l}^{⊖} - \frac{0.06}{1} l o g \frac{[F e^{2 +}]}{[F e^{3 +}]}$
$= 0.80 - 0.06 l o g \frac{0.01}{0.01}$
$= 0.80$

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Similar questions

F e^{3 +} | F e^{2 +}

25^{o}

F e^{3 +} | F e^{2 +}

F e^{2 +}

10

F e^{3 +}

E_{F e^{3 +} | F e^{2 +}}^{0} = 0.77 V

F e^{2 +} + 2 e^{-} \to F e; E^{0} = - 0.440 V

F e^{3 +} + 3 e^{-} \to F e; E^{0} = - 0.036

F e^{2 +} + 2 e \to F e

F e^{3 +} + 3 e \to F e

- 0.440

- 0.036

(E^{0})

F e^{3 +} + e \to F e^{2 +}

F e^{2 +} + 2 e^{-} \to F e, E^{o} = - 0.440

F e^{3 +} + 3 e^{-} \to F e, E^{o} = - 0.036

(E^{o})

F e^{3 +} + e^{-} \to F e^{2 +}

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