Atomic mass of calcium =40
Atomic mass of chlorine(2)=35.5×2=71.
Formula unit mass of CaCl2=40+71=111g.
4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid.
What mass of calcium chloride is formed? [Relative molecular mass of calcium chloride is 111].
4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid. (i) Write the equation for the reaction. (ii) What is the mass of 4.5 moles of calcium carbonate? (Relative molecular mass of calcium carbonate is 100). (iii) What is the volume of carbon dioxide liberated at stp? (iv) What mass of calcium chloride is formed? (Relative molecular mass of calcium chloride is 111) (v) How many moles of HCl are used in this reaction?