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Question

Calculate the relative molecular mass[molecular weight]of 290 ml.of a gas 'A' at 17*C and 1520 mm pressure which weighs 2.73 g at s.t.p.[1 litre of hydrogen at s.t.p weighs 0.09 g.]

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Solution

1. According to Avogadro's law :

Molecular mass = Mass of one mole of gas at STP2×mass of one hydrogen atom at STP
2. Mass of one hydrogen atom at STP = 1.67 × 10-24g
3. Also according to the same law :

p1V1n1T1 = p2V2n2T2 = constant

4. So,
n = pVRT = 1520 × 290×10-38.314 × 290 = 0.182
4. Mass of 0.182 moles is 2.73g
So,
Mass of 1 mole = 2.730.182= 15g
3. Molecular mass = 152×1.67×10-24g = 111.11g152×1.67×10-24g = 111.11g

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