Calculate the relative molecular masses of:
Ammonium chloroplatinate $(N H_{4})_{2} P L C l_{6}$

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Solution

Ammonium chloroplatinate $(N H_{4}) 2 P t C l_{6}$
$= (14 \times 2) + (1 \times 8) + 195.08 + (35.5 \times 6)$
$= 28 + 8 + 195.08 + 213$
$= 444.08$

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Calculate the relative molecular masses of:Ammonium chloroplatinate (NH4)2PLCl6

Ammonium chloroplatinate (NH4)2PtCl6=(14×2)+(1×8)+195.08+(35.5×6)=28+8+195.08+213=444.08

Calculate the relative molecular masses of:
Ammonium chloroplatinate $(N H_{4})_{2} P L C l_{6}$

Ammonium chloroplatinate $(N H_{4}) 2 P t C l_{6}$
$= (14 \times 2) + (1 \times 8) + 195.08 + (35.5 \times 6)$
$= 28 + 8 + 195.08 + 213$
$= 444.08$