Calculate the residue obtained on strongly heated 2.76 grams of AG2CO3

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Solution

The decomposition of silver carbonate
2Ag₂CO₃_(s) → 4Ag_(s) + 2CO_2(g) + O₂_(g)
Here,
2 moles of Ag₂CO₃gives 4 moles of Ag
Thus, 552 g of Ag₂CO₃gives 432 g of Ag
Molar mass of Ag₂CO₃= 276 g
Molar mass of Ag = 108 g
Hence,
Amount of Ag obtained = (432/552) x 2.76 = 2.16 g of Ag

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